I really dislike long simplification times 4 questions so I will jsut put the answers on some of them
1. remember that the denomenator cannot equal zero so find what values will and restrict them
the answer is the third one or [tex] \frac{3}{(x+6)(x-1)} [/tex]
2. second one
(3x-2)/(5x)
3. what you would do is factor the top and divide factors making ones
answer is the fourth one or [tex] \frac{2(3x^{2}-7)}{2x^{2}+3} [/tex]
4. find the LCM of the denoemators
4x and 2
4x=2 times 2 times x
2=2
LCM=4x
answer is the third one or 4x
ANSWERS:
1. third
2. second
3. fourth
4. third
