Question

A marble is drawn at random first from a jar containing four black and four white marbles, and then from a jar containing six black and two white marbles. What is the probability of drawing two black marbles?

Answer 1

The probability of drawing two black marbles is 3/8. The first jar has 4/8 and the second jar has 6/8. Therefore, (4/8)*(6/8) = 3/8.

Answer 2

Answer:

Probability of drawing two black marbles is $\frac{3}{8}$

Step-by-step explanation:

Given that a marble is drawn at random first from a jar containing four black and four white marbles, and then from a jar containing six black and two white marbles.

we have to find the probability of drawing two black marbles.

First we find out the probability of drawing first black marble from a jar containing four black and four white marbles

Hence, P(first black marble) = $\frac{no. of black marble}{Total no. of marbles}$ = $\frac{4}{8} = \frac{1}{2}$

now, we find out the probability of drawing second black marble  from a jar containing six black and two white marbles.

Hence, P(second black marble) = $\frac{no. of black marble}{Total no. of marbles}$ = $\frac{6}{8} = \frac{3}{4}$

Therefore, the probability of drawing two black marbles is

$\frac{1}{2}.\frac{3}{4} = \frac{3}{8}$