Respuesta :
we have that
point B (-3,-2)
point C (0,2)
the distance between B and C is
d=√(y2-y1)²+(x2-x1)²--------> d= √(2+2)²+(0+3)²-------> d=√25
d=5 units
the answer is
the length of segment BC is 5 units
using a graph tool
see the attached figure
point B (-3,-2)
point C (0,2)
the distance between B and C is
d=√(y2-y1)²+(x2-x1)²--------> d= √(2+2)²+(0+3)²-------> d=√25
d=5 units
the answer is
the length of segment BC is 5 units
using a graph tool
see the attached figure

Answer:
point B (-3,-2)
point C (0,2)
the distance between B and C is
d=√(y2-y1)²+(x2-x1)²--------> d= √(2+2)²+(0+3)²-------> d=√25
d=5 units
the answer is
the length of segment BC is 5 units
i do flvs and it is right Step-by-step explanation: