Question

How many grams of O2 is produced if you start with 12.5 grams of NaClO3?

2NaClO3(s) --> 2NaCl(s) + 3O2(g)

A) 5.64 grams O2
B) 23.1 grams O2
C) 0.35 grams O2
D) 36.8 grams O2

Answer 1

According to balanced chemical equation 212 g (2 moles) of NaClO3 on complete consumption produces 96 g (3 moles) of O2. So, using this as a reference point the amount of O2 produced by consuming 12.5 g of NaClO3 will be calculated as,

212 g of NaClO3 produced / 12.5 g NaClO3 will produce = 96 g of O2 / x

Solving for x,

x = 12.5 g /212 g x 96 g

x = 5. 66 g

So, the correct answer is A.