Which linear inequality is represented by the graph?

Answer:
[tex]y\leq \frac{1}{3}x-1.3[/tex]
Explanation:
First we find the slope of the line that passes through the two given points. The formula for slope is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Using our two points, we have
[tex]m=\frac{-0.3--1.3}{3-0}=\frac{-0.3+1.3}{3-0}=\frac{1}{3}[/tex]
The y-intercept of a line is the point where it crosses the y-axis. The graph gives us this; it is -1.3.
In slope-intercept form, this gives us the equation [tex]y=\frac{1}{3}x-1.3[/tex].
The graph is shaded below this line and the line is solid. This means the inequality is less than or equal to, giving us
[tex]y\leq \frac{1}{3}x-1.3[/tex]
The line represents the inequality y [tex]\leqslant \dfrac{1}{3}x - 1.3[/tex]. Hence, [tex]\boxed{{\text{Option A}}}[/tex] is correct.
Further explanation:
The linear equation with slope [tex]m[/tex] and intercept [tex]c[/tex] is given as follows.
[tex]\boxed{y = mx + c}[/tex]
The formula for slope of line with points [tex]\left( {{x_1},{y_1}} \right)[/tex] and [tex]\left( {{x_2},{y_2}} \right)[/tex] can be expressed as,
[tex]\boxed{m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}[/tex]
Given:
The inequalities are as follows.
A. [tex]y \leqslant \dfrac{1}{3}x - 1.3.[/tex]
B. [tex]y \leqslant \dfrac{1}{3}x - \dfrac{4}{3}.[/tex]
C. [tex]y \geqslant \dfrac{1}{3}x - \dfrac{4}{3}.[/tex]
D. [tex]y \geqslant \dfrac{1}{3}x - 1.3.[/tex]
Explanation:
The line intersects y-axis at [tex]\left( {0, - 1.3} \right)[/tex], therefore the [tex]y-[/tex] intercept is [tex]-1.3.[/tex]
The points are [tex]\left( {0, - 1.3} \right)[/tex] and [tex]\left( {3, - 0.3} \right).[/tex]
The slope of the line can be obtained as follows.
[tex]\begin{aligned}m&= \frac{{ - 0.3 - \left( { - 1.3} \right)}}{{3 - 0}}\\&= \frac{{ - 0.3 + 1.3}}{3}\\&= \frac{1}{3}\\\end{ aligned}[/tex]
The slope of the line is [tex]m=\dfrac{1}{3}.[/tex]
Now check whether the inequality included origin or not.
Substitute [tex]\left( {0,0} \right)[/tex] in the option A.
[tex]\begin{aligned}0&\leqslant \frac{1}{3}\left( 0 \right) - 1.3 \hfill \\0 &\leqslant - 1.3 \hfill\\\end{aligned}[/tex]
[tex]0[/tex] is not less than [tex]-1.3[/tex] which means that the inequality doesn’t includes origin.
The line represents the inequality y [tex]\leqslant \dfrac{1}{3}x - 1.3. \boxed{{\text{Option A}}}[/tex] is correct.
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear inequalities
Keywords: numbers, slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.