Respuesta :
You can solve for sides of a triangle using the following equation.
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
The angles of the border of the plot would be as follows:
[tex]15.87\\23.97\\140.16[/tex]
Find the angles
Given that,
The edges of the triangular plot = [tex]35 m, 52 m, and 82 m[/tex]
Using the formula,
[tex]A = arccos (b^2 + c^2 - a^2/2bc)[/tex]
By putting the values, we can determine the measures of the angles as:
[tex]=[/tex] inverse cosine([tex](b^2 +c^2 - a^2/2bc)[/tex]
∵ We get,
[tex]15.87\\23.97\\140.16[/tex]
Thus, the above answers are correct.
Learn more about "Plot" here:
brainly.com/question/13196133