Respuesta :
Let [tex]X[/tex] be a random variable denoting the number of inoculated people in a population of size [tex]n[/tex] that contract this disease. [tex]X[/tex] is said to be binomially distributed with probability [tex]p=0.2[/tex], or [tex]X\sim\mathcal B(83,0.2)[/tex].
So the probability that exactly 10 of 83 people get the disease, despite inoculation against it, is
[tex]\mathbb P(X=10)=\dbinom{83}{10}0.2^{10}(1-0.2)^{83-10}\approx0.0209842[/tex]
So the probability that exactly 10 of 83 people get the disease, despite inoculation against it, is
[tex]\mathbb P(X=10)=\dbinom{83}{10}0.2^{10}(1-0.2)^{83-10}\approx0.0209842[/tex]