There is a 20% probability that a person inoculated with a particular vaccine will get the disease anyway. A county healthy office inoculates 83 people. What is the probability that exactly 10 of them will get the disease at some point in their lives?

Respuesta :

Let [tex]X[/tex] be a random variable denoting the number of inoculated people in a population of size [tex]n[/tex] that contract this disease. [tex]X[/tex] is said to be binomially distributed with probability [tex]p=0.2[/tex], or [tex]X\sim\mathcal B(83,0.2)[/tex].

So the probability that exactly 10 of 83 people get the disease, despite inoculation against it, is

[tex]\mathbb P(X=10)=\dbinom{83}{10}0.2^{10}(1-0.2)^{83-10}\approx0.0209842[/tex]

Answer:

B. 0.0210

Explanation:

I got it correct in my test :)

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