You are given
the volume of the container which is 450mL and the number of grams of iron(III)
chloride or FeCl3. You are required to get the concentration of FeCl3. The concentration
pertains to the molarity of the solution with an equation of mol of solution
per liter of solvent. The molar mass of FeCl3 is 162.2 g/mol. Convert grams of
FeCl3 to moles.
200 g FeCl3
(1 mol FeCl3/162.2 g FeCl3) = 1.233 mol FeCl3
Then convert
450mL of solution to liters. 450mL (1 liter/1000 mL) = 0.45 L
M (molarity)
= moles of solute/L of solvent
M (molarity)
= 1.233 mol FeCl3/0.45 L
M (molarity)
= 2.74 mol/L or 2.74M FeCl3
