Question

how many liters of 4M solution can be made using 100 grams of lithium bromide

Answer 1

Molar mass of LiBr (mm )= 86.845 g/mol

Molarity ( M ) = 4 M 

Mass of solute ( m ) = 100 g

Volume ( V ) = in liters ?

V = m / mm  * M

V = 100 / 86.845 * 4

V = 100 / 347.38

V = 0.2875 L

hope this helps!.