moles of HCl = 1 * 0.0034 L = 0.0034 m
when the total volume = 0.04 L
[HCl] = 0.0034 / 0.04L = 0.085 M
then we need to get moles of AgNO3 = 0.0022 * 0.0048L = 0.00001 m
[AgNO3] = 0.00001 / 0.04 L = 0.00025 M
when Qsp = [Ag+][Cl-]
=0.00025 * 0.085 = 2.1x10^-5
when Qsp > Ksp ∴ supersaturated salt will be precipitated untile Qsp becomes equal Ksp
So because of Qsp > Ksp
∴ AgCl will be precipitated