Question

A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (3.30 m, 5.20 m) while a constant force acts on it. the force has magnitude 9.70 n and is directed at a counterclockwise angle of 111.° from the positive direction of the x axis. how much work is done by the force on the coin during the displacement?

Answer 1

Work = force x distance x cos (theta) where theta is the angle between the force and the direction of motion 

component of force in x direction = 9.70N cos 111 = -3.48 N
component of force in y direction = 9.70 sin 111 = 9.06 N

Adding the two = -3.48 x 3.30 m + 9.06N x 5.20 m

= 11.484 + 47.112

= 58.60 Joules