Question

use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

Answer 1

5x= 6x^2 -3
6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- sq root (25 -(4*6*-3)] / 12
x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- 9.84886] / 12
x1 = 1.237405  
x2 = -0.404072