I'll do the first one.
Convert the statements into equations, we can use 'n' for nickels and 'd' for dimes.
"Jennifer has $1.15 in nickels and dimes."
[tex]\sf 0.05n+0.10d=1.15[/tex]
"a total of 16 coins"
[tex]\sf n+d=16[/tex]
Solve for one of the variables in the 2nd equation, then plug that into the first equation:
[tex]\sf n+d=16[/tex]
Subtract d to both sides:
[tex]\sf n=16-d[/tex]
Now input '16 - d' for 'n' in the first equation:
[tex]\sf 0.05n+0.10d=1.15[/tex]
[tex]\sf 0.05(16-d)+0.10d=1.15[/tex]
Distribute 0.05 into the parenthesis(we do this by multiplying it to every term inside of it):
[tex]\sf 0.8-0.05d+0.10d=1.15[/tex]
Combine like terms(-0.05d + 0.10d = 0.05d):
[tex]\sf 0.8+0.05d=1.15[/tex]
Subtract 0.8 to both sides:
[tex]\sf 0.05d=0.35[/tex]
Divide 0.05 to both sides:
[tex]\sf d=7[/tex]
Now we can plug this into any of the two equations to find 'n':
[tex]\sf n+d=16[/tex]
[tex]\sf n+7=16[/tex]
Subtract 7 to both sides:
[tex]\sf n=9[/tex]
So she has 9 nickels and 7 dimes.