Respuesta :

iGreen
I'll do the first one.

Convert the statements into equations, we can use 'n' for nickels and 'd' for dimes.

"Jennifer has $1.15 in nickels and dimes."
[tex]\sf 0.05n+0.10d=1.15[/tex]

"a total of 16 coins"
[tex]\sf n+d=16[/tex]

Solve for one of the variables in the 2nd equation, then plug that into the first equation:

[tex]\sf n+d=16[/tex]

Subtract d to both sides:

[tex]\sf n=16-d[/tex]

Now input '16 - d' for 'n' in the first equation:

[tex]\sf 0.05n+0.10d=1.15[/tex]

[tex]\sf 0.05(16-d)+0.10d=1.15[/tex]

Distribute 0.05 into the parenthesis(we do this by multiplying it to every term inside of it):

[tex]\sf 0.8-0.05d+0.10d=1.15[/tex]

Combine like terms(-0.05d + 0.10d = 0.05d):

[tex]\sf 0.8+0.05d=1.15[/tex]

Subtract 0.8 to both sides:

[tex]\sf 0.05d=0.35[/tex]

Divide 0.05 to both sides:

[tex]\sf d=7[/tex]

Now we can plug this into any of the two equations to find 'n':

[tex]\sf n+d=16[/tex]

[tex]\sf n+7=16[/tex]

Subtract 7 to both sides:

[tex]\sf n=9[/tex]

So she has 9 nickels and 7 dimes.
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