For this use the law of sines:
[tex] \sin( \alpha ) \div a = \sin( \beta ) \div b \\ \sin( \alpha ) \div 11 = \sin(103) \div 16[/tex]
[tex] \frac{ \sin( \alpha ) }{11} = \frac{0.97}{16} [/tex]
cross-multiply:
16×sin (J) = 11×0.97
sin(J) = 10.72/16
sin(J) = 0.67
hit the "arcsin" button on your calculator:
[tex]{ \sin}^{ - 1} (0.67) = 42.06 = 42.1 \: deg[/tex]
therefore answer B. 42 is the correct answer!!
