babykay4
babykay4
19-03-2018
Mathematics
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[tex]x ^{2} - 10x + 16 = 0[/tex]
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jdoe0001
jdoe0001
19-03-2018
[tex]\bf x^2\stackrel{-8-2}{-10}x+\stackrel{(-8)(-2)}{16}=0\implies (x-8)(x-2)=0\implies x= \begin{cases} 8\\ 2 \end{cases}[/tex]
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