Respuesta :
[tex]\bf ~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{llcccl}
& 6 x^2& +4 x& -3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad \qquad
x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]
[tex]\bf x=\cfrac{-4\pm\sqrt{4^2-4(6)(-3)}}{2(6)}\implies x=\cfrac{-4\pm\sqrt{16+72}}{12} \\\\\\ x=\cfrac{-4\pm\sqrt{88}}{12}\implies x=\cfrac{-4\pm\sqrt{4\cdot 22}}{12}\implies x=\cfrac{-4\pm\sqrt{2^2\cdot 22}}{12} \\\\\\ x=\cfrac{-4\pm 2\sqrt{22}}{12}\implies x=\cfrac{2(-2\pm 1\sqrt{22})}{12}\implies x=\cfrac{-2\pm\sqrt{22}}{6}[/tex]
[tex]\bf x=\cfrac{-4\pm\sqrt{4^2-4(6)(-3)}}{2(6)}\implies x=\cfrac{-4\pm\sqrt{16+72}}{12} \\\\\\ x=\cfrac{-4\pm\sqrt{88}}{12}\implies x=\cfrac{-4\pm\sqrt{4\cdot 22}}{12}\implies x=\cfrac{-4\pm\sqrt{2^2\cdot 22}}{12} \\\\\\ x=\cfrac{-4\pm 2\sqrt{22}}{12}\implies x=\cfrac{2(-2\pm 1\sqrt{22})}{12}\implies x=\cfrac{-2\pm\sqrt{22}}{6}[/tex]