Respuesta :

[tex]\bf ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \begin{array}{llcccl} & 6 x^2& +4 x& -3\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]

[tex]\bf x=\cfrac{-4\pm\sqrt{4^2-4(6)(-3)}}{2(6)}\implies x=\cfrac{-4\pm\sqrt{16+72}}{12} \\\\\\ x=\cfrac{-4\pm\sqrt{88}}{12}\implies x=\cfrac{-4\pm\sqrt{4\cdot 22}}{12}\implies x=\cfrac{-4\pm\sqrt{2^2\cdot 22}}{12} \\\\\\ x=\cfrac{-4\pm 2\sqrt{22}}{12}\implies x=\cfrac{2(-2\pm 1\sqrt{22})}{12}\implies x=\cfrac{-2\pm\sqrt{22}}{6}[/tex]

Answer:

Step-by-step explanation:

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