Question

A tube of tennis balls has the following measures: 4-inch diameter and a height of 8 inches. What is the surface area of the tube of tennis balls? (Use 3.14 for π.) 213.52 in.2 301.44 in.2 226.08 in.2 125.6 in.2

Answer 1

now, if the diameter of the "cylindrical" tube is 4 inches, then its radius is half that, or 2 inches,

$\bf \textit{total surface area of a cylinder}\\\\ S=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\ -----\\ r=2\\ h=8 \end{cases}\implies S=2\pi (2)(8+2) \\\\\\ S=4\pi (10)\implies S=40\pi$

Answer 2

Answer:

125.6 in.2

Step-by-step explanation:

because the radius is 2 and the height is 8 using pi it will be 125.6 in.2