payshencec21
payshencec21 payshencec21
  • 19-03-2018
  • Mathematics
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WojtekR
WojtekR WojtekR
  • 19-03-2018
[tex]8x^2y^{-2}=\dfrac{8x^2}{y^2}\\\\\\\dfrac{8\cdot(-1)^2}{2^2}=\dfrac{8\cdot1}{4}=\dfrac{8}{4}=\boxed{2}[/tex]

Answer A)
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