Respuesta :
You are given two sides of the triangle and one angle, opposite to one of the given sides, therefore you can try to apply the Law of sine:
[tex] \frac{sin M}{m} = \frac{sin N}{n} [/tex]
Let's try to solve for sin N:
sin N = [tex] \frac{n sin N}{m} [/tex]
= [tex] \frac{20 sin42}{12} [/tex]
= 1.11
As you know, there is no angle whose sine is greater than 1, therefore the correct answer is: A) the triangle does not exist because sinN/n cannot equal sinM/m
NOTE: in your question this option has a typo.
[tex] \frac{sin M}{m} = \frac{sin N}{n} [/tex]
Let's try to solve for sin N:
sin N = [tex] \frac{n sin N}{m} [/tex]
= [tex] \frac{20 sin42}{12} [/tex]
= 1.11
As you know, there is no angle whose sine is greater than 1, therefore the correct answer is: A) the triangle does not exist because sinN/n cannot equal sinM/m
NOTE: in your question this option has a typo.
Answer:
A) the triangle does not exist because sinN/n cannot equal sinM/m
Step-by-step explanation:
edg2020