Question

The Clayton family’s pool has vertices at the coordinates (0, 2), (0, 5), (2, 5), (2, 6), (5, 6), (5, 1), (2, 1), and (2, 2). If each grid square has an area of 9 square feet, what is the area of the pool?

Ps. Only use the coordinates (Do not use a coordinate table)
And explain how to show the work, thanks.

Answer 1

We should start by plotting these points on the coordinate plan and drawing the pool.

Looking at the diagram I've attached, we can split the pool into two rectangles and find the area of each.

For the smaller rectangle, with vertices $(0,2), (0,5), (2,5), (2,2)$, the length is 3 units and the width is 2 units. $A=lw=(2\ u)(3 \ u)=6 \ u^2$

For the larger rectangle with vertices $(2,6),(5,6),(5,1),(2,1)$, the length is 5 units and the width is 3 units. $A=lw=(5\ u)(3 \ u)=15 \ u^2$

$A_{total}=15 \ u^2+6 \ u^2 = 21 \ u^2$

Now remember, each square unit on the coordinate plane represents 9 square feet, so we write:

$A=21 \ u^2 \ \ \dfrac{9 \ ft^2}{u^2} = 189 \ ft^2$

Answer 2

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