Question

Number 1 to 20 are placed in a bag without replacing the first number what is the probability that the first number drawn will be odd and second one will be even

Answer 1

are there answer choices? if not for some reason i am going with 25 percent because there are 20 numbers and 10 are even and 10 are odd so the probability to get 2 odds is about 25%

Answer 2

The probability that the first number drawn will be odd and second one will be even is 0.263

The probability P(Odd, then Even) implies that, we calculate the probability that the first number drawn will be odd and second one will be even

This is calculated as:

P(Odd, then Even). = P(Odd) * P(Even, provided that the first selection is Odd)

The selection is without replacement.

So, we have:

P(Odd, then Even). = 10/20 * 10/19

Evaluate the product

P(Odd, then Even). = 0.263

Hence, the probability that the first number drawn will be odd and second one will be even is 0.263

Read more about probability at:

https://brainly.com/question/25870256