Respuesta :
4(2x-3)=x-12+7x
first distribute 4 to everything in the perentisies giving you
8x-12= x-12+7x
then you add like terms giving you
8x-12=8x-12
first distribute 4 to everything in the perentisies giving you
8x-12= x-12+7x
then you add like terms giving you
8x-12=8x-12
4(2х-3)=х-12+7х
8х-12=х-12+7х
8х-х-7х=-12+12
8х-8х=0
0=0
x is any number
(-infinite; +infinite)
8х-12=х-12+7х
8х-х-7х=-12+12
8х-8х=0
0=0
x is any number
(-infinite; +infinite)