Question

The data below shows the temperature of the water in a swimming pool over a two week period. Week 1 Day Temperature (°F) Monday 58 Tuesday 48 Wednesday 49 Thursday 61 Friday 58 Saturday 51 Sunday 39 Week 2 Day Temperature (°F) Monday 68 Tuesday 74 Wednesday 73 Thursday 75 Friday 70 Saturday 67 Sunday 63 How many degrees greater is the mean temperature in week 2 than in week 1? a0°

Answer 1

week 1$58 + 48 + 49 + 61 + 58 + 51 + 39 \\ = 364 \\ 364 \div 7 = 52$
week 2
$68 + 74 + 73 + 75 + 70 + 67 + 63 \\ = 490 \\ 490 \div 7 = 70$
difference
$70 - 52 = 18$
the difference is 18 degrees between the means

Answer 2

The mean for week 2 is 18 degrees larger than the mean for week 1.

How many degrees greater is the mean temperature in week 2 than in week 1?

On Week 1 the temperatures are:

{58F, 48F, 49F, 61F, 58F, 51F, 39F}

So the mean is:

$M = \frac{58F + 48F + 49F + 61F + 58F + 51F + 39F}{7} = 52F$

For Week 2 the temperatures are:

{68F, 74F, 73F, 75F, 70F, 67F, 63F}

So the mean is:

$M = \frac{68F + 74F + 73F + 75F + 70F + 67F + 63F}{7} = 70F$

So the mean for week 2 is:

70F - 52F = 18F

The mean for week 2 is 18 degrees larger than the mean for week 1.

If you want to learn more about means:

https://brainly.com/question/14532771

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