Respuesta :

Consider this option:
cos π/6=√3/2;
cos π/3=1/2;
tan π/6=1/√3;
tan π/3=√3

Answer:

[tex]tan\frac{\pi}{6}= \frac{1}{\sqrt3}[/tex]

[tex] tan\frac{\pi}{3}=\sqrt3[/tex]

[tex]cos\frac{\pi}{3}=\frac{1}{2}[/tex]

[tex]cos\frac{\pi}{6}=\frac{\sqrt3}{2}[/tex].

Step-by-step explanation:

[tex]cos\frac{\pi}{6}=cos 30^{\circ}[/tex]

[tex]cos30^{\circ}=\frac{\sqrt3}{2}[/tex]

Therefore, [tex]cos\frac{\pi}{6}=\frac{\sqrt3}{2}[/tex]

[tex]cos\frac{\pi}{3}= cos60^{\circ}[/tex]

[tex]cos60^{\circ}=\frac{1}{2}[/tex]

Therefore,[tex]cos\frac{\pi}{3}=\frac{1}{2}[/tex]

[tex] tan\frac{\pi}{6}= tan30^{\circ}[/tex]

[tex]tan30^{\circ}=\frac{1}{\sqrt3}[/tex]

Therefore, [tex]tan\frac{\pi}{6}=\frac{1}{\sqrt3}[/tex]

[tex]tan\frac{\pi}{3}=tan60^{\circ}[/tex]

[tex]tan60^{\circ}=\sqrt3[/tex]

Therefore, [tex]tan\frac{\pi}{3}=\sqrt3[/tex]

ACCESS MORE