S=4πR2
V=43πR3
To double the volume, we have to increase the radius by multiplying it by 3√2.
let R1=R3√2
Then the volume of a sphere with radius R1 will be
V1=43πR31=43π(R3√2)3=83πR3 - twice larger than original volume.
With radius R1=R3√2 the surface area of a new sphere will be
4πR21=4πR2(3√2)2=43√4πR2
The ratio of the new surface area to the old one equals to
43√4πR24πR2=3√4