Question

A 33.0 g iron rod, initially at 22.7 ∘c, is submerged into an unknown mass of water at 63.3 ∘c, in an insulated container. the final temperature of the mixture upon reaching thermal equilibrium is 58.5 ∘c. part a what is the mass of the water? express your answer to two significant figures and include the appropriate units.

Answer 1

The specific heat capacity of iron = 0.450 J/g°C
and the specific heat water = 4.18 J/g°C
Heat gained by iron; 
= 33 × 0.450 (58.5-22.7)
= 531.63 J
Heat lost by water; assuming the mass of water m
= m × 4.18 × (63.3 - 58.5)
= 20.064m
But; heat gained = heat lost
 20.064 m = 531.63
            m = 26.497 g
Therefore, the mass of water is 26.497 g