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The answer is 15.0 mol ammonium sulfate. This is a stoichiometric problem. For the calculations, please refer to the attachment.
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15.0 moles of ammonium sulfate are formed by the reaction of 30.0 moles of ammonia with sulfuric acid.

Let's consider the reaction between ammonia and sulfuric acid to produce ammonium sulfate.

2 NH₃ + H₂SO₄ ⇒ (NH₄)₂SO₄

The molar ratio of NH₃ to (NH₄)₂SO₄ is 2:1. The moles of (NH₄)₂SO₄ produced from 30.0 moles of NH₃ are:

[tex]30.0 mol NH_3 \times \frac{1mol(NH_4)_2SO_4}{2molNH_3} = 15.0 mol(NH_4)_2SO_4[/tex]

15.0 moles of ammonium sulfate are formed by the reaction of 30.0 moles of ammonia with sulfuric acid.

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