Question

6 times the sum of 3 odd numbers is -18 find the integers

Answer 1

6(x+[x+2]+[x+4])=-18

6x+6x+12+6x+24=-18
18x+36=-18
18x=-54
x=-3

1st integer is -3
2nd is -1
3rd is  1

6(-3+(-1)+1)=-18
6(-3)=-18
-18 = -18