Question

The specific heat of a certain type of metal is 0.128 j/(g·°c). what is the final temperature if 305 j of heat is added to 26.5 g of this metal initially at 20.0 °c?

Answer 1

We know the heat gained

#DeltaH=mxxsxx(t_2-t_1)#

where

#DeltaH=305J#
#m->"mass"=83g#

#s->"sp heat"=0.128" J/(g^@C)#

#t_1->"initial temperature"=20^@C#

#t_2->"final temperature"=?#

So

#DeltaH=mxxsxx(t_2-t_1)#

#=>305J=83gxx0.128J/(g^@C)xx(t_2-20)^@C#

#=>t_2-20=305/(83xx0.128)#

#=>t_2=48.7^@C#