Question

When you push a 1.87-kg book resting on a tabletop, it takes 2.02 n to start the book sliding. once it is sliding, however, it takes only 1.47 n to keep the book moving with constant speed. what is the coefficient of static friction between the book and the tabletop?

Answer 1

$F_{friction} = \mu N = \mu mg \\ \\ \mu = \frac{F_{friction}}{mg}$

F static friction
m mass
g gravitational acceleration
μ static friction coefficient

$\mu = \frac{2.02N}{1.87kg(9.81 \frac{m}{s^2} )} = 0.11$