Respuesta :
Answer: [tex]6y^3 + 17y^2 + 22y + 15[/tex]
Step-by-step explanation:
Here, the given expression, [tex](2y+3). (3y^2+4y+5)[/tex]
By applying distribution property in second bracket,
= [tex]3y^2(2y+3)+4y(2y+3)+5(2y+3)[/tex]
= [tex]6y^3+9y^2+8y^2 +12y+10y+15[/tex] ( again by applying distributive property)
= [tex]6y^3+17y^2 +22y+15[/tex] ( by adding like terms)
Thus, [tex](2y+3). (3y^2+4y+5)[/tex]= [tex]6y^3+17y^2 +22y+15[/tex]