Answer:
0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.
Explanation:
[tex]H_2SO_4+Ca(OH)_2\rightarrow CaSO_4+2H_2O[/tex]
1 mol of sulfuric acid reacts or neutralizes with 1 mol of calcium hydroxide.
Then 0.10 mole of calcium hydroxide will be neutralized by:
[tex]\frac{1}{1}\times 0.10 mol= 0.10 mol[/tex] of sulfuric acid
0.10 mol of sulfuric acid will neutralize 0.10 mol of calcium hydroxide.