Respuesta :
Let
x------------> length major side parallelogram
y------------> length minor side parallelogram
we know that
[perimeter]=(2x+2y)
Po=(2x+2y)
If the dimensions of a parallelogram are increased by a factor of two
then
x1=2x
y1=2y
P1=2x1+2y1----------> 2*[2x]+2*[2y]--------> P1=2*[2x+2y]
P1=2*Po
the answer is
the new perimeter increase by a factor of two
x------------> length major side parallelogram
y------------> length minor side parallelogram
we know that
[perimeter]=(2x+2y)
Po=(2x+2y)
If the dimensions of a parallelogram are increased by a factor of two
then
x1=2x
y1=2y
P1=2x1+2y1----------> 2*[2x]+2*[2y]--------> P1=2*[2x+2y]
P1=2*Po
the answer is
the new perimeter increase by a factor of two
Answer:
increase by a factor of two
Step-by-step explanation:
Given that dimension of a parallelogram are increased by a factor of 2.
Let the sides of the parallelogram be l and w.
Then perimeter = 2(l+w)
When each side is increased by a scale factor of 2, we get new dimensions as
2l and 2w
Hence new perimeter = 2(2l+2w) = 4(l+w)
= twice as old perimeter
Hence increase by a factor of two