The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Determine the formula for potassium superoxide.
First we need to find the number of moles of both K and O reacted K - 0.779 g / 39 g/mol = 0.02 mol the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g O₂ moles = 0.638 g / 32 g/mol = 0.02 mol the number of both K and O₂ moles reacted are equal therefore stoichiometry of K to O₂ reacted are 1:1 then the formula of potassium superoxide is KO₂
