The given equation is :
[tex] 2x^{2} =27+3x [/tex]
Now let us write it in standard form:
[tex] 2x^{2} -3x-27=0 [/tex]
Comparing it with general standard form:
[tex] ax^{2} +bx+c=0 [/tex]
So we have a=2, b=-3 and c=-27
First option is correct answer .