Respuesta :
I believe that the choices for this question are:
C2H4O2, C4H8O4 CH2O, C6H12O6 C3H6O3, C6H12O6 C2H4O2, C6H12O6
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180
C2H4O2, C4H8O4 CH2O, C6H12O6 C3H6O3, C6H12O6 C2H4O2, C6H12O6
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180
The molecular formula of the compound is C10H20O.
The question is incomplete, the complete question is;
Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005-g sample of menthol is combusted, producing 0.2829 g of CO2 and 0.1159 g of H2O. What is the empirical formula for menthol? If the compound has a molar mass of 156 g/mol, what is its molecular formula?
First we have to obtain the mass/moles of each element;
Mass of C;
0.2829 g/44g/mol * 12 g/1 mol = 0.077 g of C
Number of moles of C = 0.077 g of C/ 12 g/mol = 0.0064 moles
Mass of H;
0.1159 g/18g/mol * 2g/1mol = 0.0129 g of H
Number of moles of H = 0.0129 g of H/1 g/mol = 0.0129 moles
Mass of O = 0.1005 g - (0.077 g + 0.0129 g)
Mass of O = 0.1005 g - 0.0899
= 0.0106 g
Number of moles of O = 0.0106 g/ 16 g/mol = 0.000663 moles
Dividing through by the lowest number of moles;
C - 0.0064/0.000663 H - 0.0129/0.000663 O - 0.000663/0.000663
C - 10 H - 20 O - 1
Empirical formula; C10H20O
Since the molecular formula is 156 g/mol
(C10H20O)n = 156
Where n is the number of each atom in the compound
(120 + 20 + 16)n = 156
156n = 156
n = 1
Hence the molecular formula of the compound is C10H20O.
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