Respuesta :

I believe that the choices for this question are:
C2H4O2, C4H8O4 CH2O, C6H12O6 C3H6O3, C6H12O6 C2H4O2, C6H12O6 
 
The answer to this based on the molar masses given is:
C2H4O2, C6H12O6 
 
To prove calculate the molar mass:
C2H4O2 = 2*12 + 4*1 + 2*16 = 60
C6H12O6 = 6*12 + 12*1 + 6*16 = 180

The molecular formula of the compound is C10H20O.

The question is incomplete, the complete question is;

Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005-g sample of menthol is combusted, producing 0.2829 g of CO2 and 0.1159 g of H2O. What is the empirical formula  for menthol?  If the compound has a molar mass of 156 g/mol, what is its molecular formula?

First we have to obtain the mass/moles of each element;

Mass of C;

0.2829 g/44g/mol * 12 g/1 mol  = 0.077 g of C

Number of moles of C =  0.077 g of C/ 12 g/mol = 0.0064 moles

Mass of H;

0.1159 g/18g/mol * 2g/1mol = 0.0129 g of H

Number of moles of H = 0.0129 g of H/1 g/mol = 0.0129 moles

Mass of O = 0.1005 g - (0.077 g + 0.0129 g)

Mass of O = 0.1005 g - 0.0899

= 0.0106 g

Number of moles of O =  0.0106 g/ 16 g/mol = 0.000663 moles

Dividing through by the lowest number of moles;

C - 0.0064/0.000663      H - 0.0129/0.000663    O - 0.000663/0.000663

C - 10                               H - 20                               O - 1

Empirical formula; C10H20O

Since the molecular formula is 156 g/mol

(C10H20O)n = 156

Where n is the number of each atom in the compound

(120 + 20 + 16)n = 156

156n = 156

n = 1

Hence the molecular formula of the compound is C10H20O.

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