We need to go back to the definition of pressure. It is the ratio of Force applied (normal to a surface) over that surface. Hence, we have that F=p*A or [tex]p= \frac{F}{A} [/tex]. The normal force on the table is equalt to the weight of the ballon since gravitational forces from the Earth have downwards direction.
Substituting the known values, we get that p=1306.67 P= 1306.67 [tex] \frac{N}{m^2} [/tex]. That is regarding the measure of P. The direction of the pressure is always the same as that of the force, in this case downwards (towards the center of the Earth).