Question

how many molecules are there in 9.34 grams of water

Answer 1

Answer: $3.13\times 10^{23}molecules$

Explanation: To calculate the moles, we use the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{9.34g}{18g/mol}=0.52mol$  

1 mole of water contains=$6.023\times 10^{23}molecules$ of water

0.52 moles of water contain=$\frac{6.023\times 10^{23}}{1}\times 0.52=3.13\times 10^{23}molecules$ of water

Answer 2

One or more than one atoms bonds and makes up the molecules, it can be the same or different atoms that make up the compounds. Molecules present in the 9.34 gm of water are $\rm 3.13 \times 10^{23}$.

What is the formula for calculating molecules?

Given,

Mass of the water (m) = 9.34 gm

The molar mass of the water (M)= 18 g/mol

From the mass and the molar mass number of the moles can be estimated:

$\rm Moles (n) = \dfrac{\;\rm Mass}{\rm Molar \;mass}$

Substituting values in the above formula:

$\begin{aligned}\rm n &= \dfrac{9.34\;\rm g}{18\;\rm g/mol}\\\\&= 0.52\;\rm mol\end{aligned}$

We know that,

1 mole of water = $\rm 6.023 \times 10^{23}$ molecules of water

0.52 moles of water = X molecules

Solving for X:

$\begin{aligned} \rm X &= 0.52 \times \rm 6.023 \times 10^{23}\\\\&= \rm 3.13 \times 10^{23}\end{aligned}$

Therefore, $\rm 3.13 \times 10^{23}$ molecules are present.

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