Respuesta :
This problem can be solved by using ideal gas equation PV=nRT. The unit used in the pressure is kPa so you will need to convert it. The temperature also use Kelvin, you will need to convert it if you want it in C.
The calculation would be:
PV= nRT
16.4 atm * (101.35kPa/atm) * 18.35 L = 12.2 mol *T * (8.314 L*kPa/mol*K)
T=30500 /101.4308
T= 300.70 °K = 27.55 °C
The calculation would be:
PV= nRT
16.4 atm * (101.35kPa/atm) * 18.35 L = 12.2 mol *T * (8.314 L*kPa/mol*K)
T=30500 /101.4308
T= 300.70 °K = 27.55 °C
The temperature of 12.2 moles gas in a 18.35 l tank at 16.4 atm is 3,071.7 K or 2,798.5 degree celsius.
How do we calculate temperature?
Temperature of the gas will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure of gas = 16.4 atm
V = volume of gas = 18.35 L
n = moles of gas = 12.2 mol
R = universal gas constant = 0.0821 L.atm / K.mol
T = temperature of the gas = ?
On putting all these values on the above equation, we get
T = (167.4)(18.35) / (12.2)(0.0821) = 3,071.7 K = 2,798.5 degree celsius.
Hence required temperature is 3,071.7 K or 2,798.5 degree celsius.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/1056445
