Question

$1,\frac{1}{8},\frac{1}{27},\frac{1}{64},...,\frac{1}{n^{3}},...$
The denominator of the seventh term is
A.] 125
B.] 216
C.] 343
D.] 513

Answer 1

Answer: option C) 343

Justification:

The sequence of the denominators is:

term         denominator

1               1 = 1^3
2               8 = 2^3
3               27 = 3^3
4               64 = 4^3

5               5^3 = 125
6               6^3 = 216
7               7^3 = 343

And that is the term searched. So, the answer is the option C) 343.

Answer 2

Answer:

the answer is C.] 343