Respuesta :
Recall that i²=-1, and i^4=1
divide 233 by 4 to find the remainer: 233÷4=58, remainder is 1
so the result is i
i^233=(i^4)^58×i=1^58×i=i
divide 233 by 4 to find the remainer: 233÷4=58, remainder is 1
so the result is i
i^233=(i^4)^58×i=1^58×i=i