Question

In the month of January, a certain restaurant claimed it sold 9,000 burgers and expects sales to grow at a rate of 4.8% per month over the next year. Which formula will determine the number of burgers the restaurant expects to sell this year?

Answer 1

Answer:

$y=9000(1.048)^x$

Step-by-step explanation:

This will be an exponential growth problem.  This is because the amount of burgers is expected to change at the same rate every month.

These equations are of the form

$y=a(1+r)^x$,

where a is the original amount, r is the growth rate and x is the amount of time.

In this problem, the original amount, a, is 9000.

The rate of growth is 4.8%; 4.8% = 4.8/1000 = 0.048

This gives us

$y=9000(1+0.048)^x\\\\y=9000(1.048)^x$

Answer 2

Answer:

The answer is 9000(1.048)^t  {limit from n = 1 to n = 12}.

Step-by-step explanation: