Question

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11 feet long? x (to the nearest tenth) =

Answer 1

the complete question in the attached figure

we know that
if the weights are perfectly balanced
40*(x)=50*(11-x)
40x=550-50x------------> 50x+40x=550--------------> x=6.11

x=6.1 ft

the answer is 6.1 ft

Answer 2

Answer:

$x=6.11  feet$

Step-by-step explanation:

Given that in a fulcrum weights are perfectly balanced.

One side 40 lb weight is there and another side 50 lb weight is given

Let x be the length of 40 lb weight from fulcrum.  Then 50 lbs is at a distance of 11-x.

Then we have since weights are perfectly balanced

$40x = 50(11-x)\\90x=550\\x=6.111$

Thus we get $x=6.11$feet