Question

how many grams of NA required to react with 75.0 gramsof CL2?

Answer 1

cl2 has a molar mass of 71g/mole.
75g/71g/mole=1.06moles of cl2
2Na+Cl2→2NaCl
therefore, for every one mole of cl2 there are 2 moles of Na.
1.06*2=2.12moles of Na
every mole of Na is 22.98g
2.12moles *22.98g/mole= 48.72g Na

answer is 42.72grams