Question

Which comparison is correct for the values of f(x) and g(x) when x=−1 ?



Function A: f(x)= −x^2+1

Function B:



f(−1)>g(−1)

f(−1)=g(−1)

f(−1)

Answer 1

Answer:

$f(-1)>g(-1)$

Step-by-step explanation:

we are given

$f(x)=-x^2+1$

We can plug x=-1 and find f(x)

we get

$f(-1)=-(-1)^2+1$

$f(-1)=-1+1$

$f(-1)=0$

now, we can find g(-1)

we can look at the table and find g(-1)

so, we get

$g(-1)=-4$

we know that

-4 is less than 0

so,

$g(-1)<f(-1)$

or we get

$f(-1)>g(-1)$