Respuesta :
if i think you are doing this by the "computer way" your answer would be 0.2 ways
Answer:
Step-by-step explanation:
The sample space, is the set of all children involved. Thus,
          n(Samples space)=n(S)=6+15+4=25.
The letters S and C represent the sets "Swam" and "built castles", clearly.
Let
E_1, E_2, E_3, E_4, E_5,E_6
be the following events, with the following number of sets:
E_1: S. Â Â Â Â n(E_1)= number of all those who swam =21.
E_2:Â S or C, but not both. Â Â Â Â n()=6+4=10, because there are 6 of those who swam but not built castles, and 4 of those who built castles but not swam.
:Â C. Â Â Â Â Â n(E_3)=15+4=19.
: S ∪ C.      n(E_4)=6+15+4=25.
:Â C, but not S. Â Â Â Â Â n(E_5)=4, as there are only 4 who built castles but not swam.
: S ∩ C.      n(E_6)15, as they are 15 who built castles and swam.
The formula for the probability P(E) Â of an event EÂ is P(E)=n(E)/n(S).
Thus, the probabilities are as follows:
P(E_1)=n(E_1)/n(S)=21/25=0.84
P(E_2)=n(E_2)/n(S)=10/25=0.4
P(E_3)=n(E_3)/n(S)=19/25=0.76
P(E_4)=n(E_4)/n(S)=25/25=1.0
P(E_5)=n(E_5)/n(S)=4/25=0.16
P(E_6)=n(E_6)/n(S)=15/25=0.6