Question

Jacobs & Johnson, an accounting firm, employs 15 accountants, of whom 9 are CPAs. If a delegation of 4 accountants is randomly selected from the firm to attend a conference, what is the probability that 4 CPAs will be selected? (Round your answer to three decimal places.)

Answer 1

1st acc = 6/14 chance 
2nd acc = 5/13 
3rd acc = 4/12 

6/14 * 5/13 * 4/12 = 0.0549450549 

round to 3 decimal places ==> 0.055
Please put me on brainlest if its correct! Thank you!

Answer 2

Using the hypergeometric distribution, it is found that there is a 0.0923 = 9.23% probability that 4 CPAs will be selected.

What is the hypergeometric distribution formula?

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

• x is the number of successes.

• N is the size of the population.

• n is the size of the sample.

• k is the total number of desired outcomes.

In this problem, there are 15 accountants, 9 are CPAs and 4 will be selected, hence N = 15, k = 9, n = 4.

The probability that 4 CPAs will be selected is P(X = 4), hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 4) = h(4,15,4,9) = \frac{C_{9,4}C_{6,0}}{C_{15,4}} = 0.0923$

0.0923 = 9.23% probability that 4 CPAs will be selected.

More can be learned about the hypergeometric distribution at https://brainly.com/question/24826394

#SPJ2