Respuesta :
I graphed the given points. A heptagon is a shape with seven sides. In the figure I graphed, I found familiar shapes like rectangle and triangles. I'll be using the formula of the triangle and rectangle when solving for its area.
Area of a triangle = (base * height) / 2
Area of a rectangle = length * width
I divided my graph into 3 parts. 1st part is the 2 triangles, 2nd part is the rectangle, 3rd part is the right triangle.
1st part
The 2 triangles each have a base of 4 units and a height of 3 units.
Area of a triangle = (base * height) / 2
A = (4 * 3)/2 = 12/2 = 6 square unit. per triangle.
Since there are 2 triangles, 6 sq.u * 2 = 12 sq.unit
2nd part
rectangle length = 8 units ; width = 3 units
Area of a rectangle = length * width = 8 * 3 = 24 sq. unit
3rd part
Right triangle: short leg = 2 units ; long leg = 8 units
Area of a right triangle = (long leg * short leg) / 2
Area of a right triangle = (8 * 2) / 2 = 16/2 = 8 sq. unit
Total area of the heptagon = 12 sq.u + 24 sq. u + 8 sq. u = 44 sq. unit.
Area of a triangle = (base * height) / 2
Area of a rectangle = length * width
I divided my graph into 3 parts. 1st part is the 2 triangles, 2nd part is the rectangle, 3rd part is the right triangle.
1st part
The 2 triangles each have a base of 4 units and a height of 3 units.
Area of a triangle = (base * height) / 2
A = (4 * 3)/2 = 12/2 = 6 square unit. per triangle.
Since there are 2 triangles, 6 sq.u * 2 = 12 sq.unit
2nd part
rectangle length = 8 units ; width = 3 units
Area of a rectangle = length * width = 8 * 3 = 24 sq. unit
3rd part
Right triangle: short leg = 2 units ; long leg = 8 units
Area of a right triangle = (long leg * short leg) / 2
Area of a right triangle = (8 * 2) / 2 = 16/2 = 8 sq. unit
Total area of the heptagon = 12 sq.u + 24 sq. u + 8 sq. u = 44 sq. unit.