Respuesta :
The general form of an explicit rule for an arithmetic sequence is
[tex]a_n=a_1+d(n-1)[/tex], where a₁ is the first term of the sequence and d is the common difference. Since we have [tex]a_n=17-5n[/tex], we know that n is multiplied by 5. That means that d must be 5, since that is the only thing that n gets multiplied in our general form. This gives us:
[tex]a_n=a_1+5(n-1) \\ \\a_n=a_1+5*n-5*1 \\ \\a_n=a_1+5n-5[/tex]
We know that we add something to 5n and then subtract 5 to get 17. Cancelling this process, we can add 5 to 17 to get 22. This gives us
[tex]a_n=22+5(n-1)[/tex]
We know that our first term, a₁, is 22 and our common difference, d, is 5.
The general form of a recursive formula for an arithmetic sequence is
[tex]a_n=a_n_-_1+d[/tex], where d is the common difference and [tex]a_n_-_1[/tex] is the previous term. We know that d is 5, so our recursive formula is
[tex]a_n=a_n_-_1+5[/tex]
[tex]a_n=a_1+d(n-1)[/tex], where a₁ is the first term of the sequence and d is the common difference. Since we have [tex]a_n=17-5n[/tex], we know that n is multiplied by 5. That means that d must be 5, since that is the only thing that n gets multiplied in our general form. This gives us:
[tex]a_n=a_1+5(n-1) \\ \\a_n=a_1+5*n-5*1 \\ \\a_n=a_1+5n-5[/tex]
We know that we add something to 5n and then subtract 5 to get 17. Cancelling this process, we can add 5 to 17 to get 22. This gives us
[tex]a_n=22+5(n-1)[/tex]
We know that our first term, a₁, is 22 and our common difference, d, is 5.
The general form of a recursive formula for an arithmetic sequence is
[tex]a_n=a_n_-_1+d[/tex], where d is the common difference and [tex]a_n_-_1[/tex] is the previous term. We know that d is 5, so our recursive formula is
[tex]a_n=a_n_-_1+5[/tex]
Answer:
[tex]a_{n} = a_{n-1}-5[/tex]
[tex]a_{1} = 12[/tex]
Step-by-step explanation: