The total power emitted by an object via radiation is:
[tex]P=A\epsilon \sigma T^4[/tex]
where:
A is the surface of the object (in our problem, [tex]A=1.25 m^2[/tex]
[tex]\epsilon[/tex] is the emissivity of the object (in our problem, [tex]\epsilon=1[/tex])
[tex]\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4)[/tex] is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is [tex]T=100^{\circ} C=373 K[/tex]
Substituting these values, we find the power emitted by radiation:
[tex]P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW[/tex]
So, the correct answer is D.